How much water really? - The Planted Tank Forum
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post #1 of 20 (permalink) Old 03-01-2014, 10:51 PM Thread Starter
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How much water really?

Does anybody know how much water is actually in a 55gal when you have 100 lbs. of substrate and about 30 lbs. of rocks?

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post #2 of 20 (permalink) Old 03-01-2014, 11:52 PM
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47.0556223

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post #3 of 20 (permalink) Old 03-02-2014, 12:07 AM
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47.0556223
Haha, thats awfully specific, you sure you aren't off by a grain of sand or two?

How'd you arrive at that value?
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post #4 of 20 (permalink) Old 03-02-2014, 12:09 AM
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It's going to be hard to tell, as tank sizes vary slightly, and the density of rocks and such vary.

Best bet would be to measure the water you put in as you fill it, but I guess that's not an option now.

Assuming the tank actually holds 55 gallons (I think the typical 55g actually holds a bit less, but not certain - if you want to find out, measure the inside in inches - a gallon is 231 cubic inches), and that your rocks/substrate are silicate with a specific gravity about 3ish...

maybe somewhere around 50 gallons?

Are you just curious, or are you trying to figure out dosing, or something else? Most of the type of dosing we do doesn't have to be that precise.
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post #5 of 20 (permalink) Old 03-02-2014, 01:32 AM
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Haha, thats awfully specific, you sure you aren't off by a grain of sand or two?

How'd you arrive at that value?
First I devised a device connected to my computer to calculate exactly how many drops were in one gallon of water. The device was really just a laser and the computer then counted how many times the beam was broken. Of course I had to write the software first since I didn't have access to public domain software. Actually there isn't any written for the particular device I built. Then using a scale accurate to 1/1000 of a dram I weighed out exactly 100 pounds of common substrates and 30 pounds of the more common rocks. the rest the computers did.

Dilution is the solution for the pollution.
Quote me as saying I was misquoted.
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post #6 of 20 (permalink) Old 03-02-2014, 02:50 AM
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I just want to know when the internet is going to invent a font for sarcasm.
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post #7 of 20 (permalink) Old 03-02-2014, 03:06 AM
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Originally Posted by Smeagol View Post
Does anybody know how much water is actually in a 55gal when you have 100 lbs. of substrate and about 30 lbs. of rocks?
I read all your post in Golem's (Smeagol's) voice. It's rather amusing.
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post #8 of 20 (permalink) Old 03-02-2014, 03:35 AM
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Originally Posted by GraphicGr8s View Post
First I devised a device connected to my computer to calculate exactly how many drops were in one gallon of water. The device was really just a laser and the computer then counted how many times the beam was broken. Of course I had to write the software first since I didn't have access to public domain software. Actually there isn't any written for the particular device I built. Then using a scale accurate to 1/1000 of a dram I weighed out exactly 100 pounds of common substrates and 30 pounds of the more common rocks. the rest the computers did.
Wow! You should patent that device quick
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post #9 of 20 (permalink) Old 03-02-2014, 03:37 AM
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Wow! You should patent that device quick
I did.
$300,000 in sales so far.

Dilution is the solution for the pollution.
Quote me as saying I was misquoted.
Once you get rid of integrity the rest is a piece of cake.
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post #10 of 20 (permalink) Old 03-02-2014, 03:38 AM
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Wonderful! You should setup a fund to educate people about technology and the aquarium, or maybe pulling people's legs!
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post #11 of 20 (permalink) Old 03-02-2014, 03:53 AM
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Well there was a slight problem there. Seems as though while I am a great inventor I suck in business. We had $300,000 in sales but it cost $350,000 to manufacture. The bright side is we will make it up in volume.

Dilution is the solution for the pollution.
Quote me as saying I was misquoted.
Once you get rid of integrity the rest is a piece of cake.
Here's to our wives and sweethearts - may they never meet.
If you agreed with me we'd both be right.
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post #12 of 20 (permalink) Old 03-02-2014, 05:32 AM
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If I calculated correctly you'll need to produce roughly 47.0556223 more units before you break even.
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post #13 of 20 (permalink) Old 03-02-2014, 05:39 AM
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Originally Posted by GraphicGr8s View Post
First I devised a device connected to my computer to calculate exactly how many drops were in one gallon of water. The device was really just a laser and the computer then counted how many times the beam was broken. Of course I had to write the software first since I didn't have access to public domain software. Actually there isn't any written for the particular device I built. Then using a scale accurate to 1/1000 of a dram I weighed out exactly 100 pounds of common substrates and 30 pounds of the more common rocks. the rest the computers did.
Does your machine work with metric, English or US drops?
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post #14 of 20 (permalink) Old 03-02-2014, 06:16 AM
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I just want to know when the internet is going to invent a font for sarcasm.
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post #15 of 20 (permalink) Old 03-02-2014, 06:36 AM
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Originally Posted by Smeagol View Post
Does anybody know how much water is actually in a 55gal when you have 100 lbs. of substrate and about 30 lbs. of rocks?
Just guess. If the substrate is 3" high in a 30" high tank, that's 1/10 of the water volume.

If you care enough, you could measure the water pressure at substrate level and with the dimensions of the tank you should be able to calculate exactly how much water is in your tank.
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