Water pressure as a function of depth
It's my understanding that water pressure is dependant on the depth of the water column, and not the total volume of the tank. Am I wrong here?
The reason I ask is because I'm in the beginning stages of building a paludarium that will be a water fall with a cascade pool. I intend to make the front, viewable portion a solid pane of glass with the access doors in the sides. The viewing area will be just shy of 36" across and I have no intention of bracing the glass in the center. The depth at the front of the tank will be no more than 12-14", but the front pane will be 54" tall, so bracing at the top would not be terribly effective. There will be glass running from front to back maybe 6" in from each side, where a land area will be situated, unless I do the lowest pool riparium style. The glass will be retained by 1/2" or 5/8" plywood (I'd rather go lighter if possible as I will likely have to move this thing at some point.). In any case, there will probably be a 24-30" section without reinforcement.
The thicker I go with the glass, the heavier this thing will become, so I'm hoping to go with 3/8" or less. I'm hoping to get away with 1/2" glass (1/4" would be nice if doable.). My thought is that there won't be a tremendous amount of pressure pushing on the front glass, but at 36"x28"x12", there will be somewhere around 50 gallons of water in the lower section (A bit less due to land area, etc.).
Does anyone have any thoughts on this matter? Maybe someone less physics challenged than myself can set me straight?