Planted Tank Obsessed

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Pfertz bottles empty, now what?
buy new ones? right!
So, I have dry ferts at home and want to reuse the bottles. I have not found a useful, straight to the point answer.
How much dry powder will each bottle need ( 500 ml, each pump is 1 ml ). What I did found is that it has to be very concentrated, so lets say I want to dose with each pump 5 gallons of water ( 1 pump = dosing 5 gallons)
some suggested to buy a digital scale and measure the amounts, no problem with that, but how much dry ferts should I add?
thanks for any help, I know this will help a lot of us
So, I have dry ferts at home and want to reuse the bottles. I have not found a useful, straight to the point answer.
How much dry powder will each bottle need ( 500 ml, each pump is 1 ml ). What I did found is that it has to be very concentrated, so lets say I want to dose with each pump 5 gallons of water ( 1 pump = dosing 5 gallons)
some suggested to buy a digital scale and measure the amounts, no problem with that, but how much dry ferts should I add?
thanks for any help, I know this will help a lot of us
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Planted Tank Obsessed
Hello my friend.
I will keep this short and to the point.
Dry ferts....check
Micro scale hundredths scale (thousandths even better)....purchase
graduated pumps (you know how much fluid they hold)....check
Answer: Download yourself 'Chuck's Planted Aquarium Calculator' via Googizzle
Chucks Planted Aquarium Calculator
It will show you the way....
I will keep this short and to the point.
Dry ferts....check
Micro scale hundredths scale (thousandths even better)....purchase
graduated pumps (you know how much fluid they hold)....check
Answer: Download yourself 'Chuck's Planted Aquarium Calculator' via Googizzle
Chucks Planted Aquarium Calculator
It will show you the way....
Eheim Pimpin 225
GTO
GTO
Planted Member
Hmm looks relatively easy to deconstruct in terms of its NPK.
All of this will be working in 1L batches, you can half to get 500ml later. I'm not about to correct for density at the moment; it'd take me a while longer to calculate that and I'm a bit tired right now. You may want to add 25% to any of these numbers. You could probably even weigh some pfertz to get a rough estimate if you wanted. You'll also want to follow along with these equations by looking up the molar mass of the compounds we're working with.
Nitrogen bottle:
5% K2O
1.75% NO3
Ingredients: Urea and KNO3
Well there's no potassium in urea, so we can find out the quantity of it by figuring out however much KNO3 doesn't take up.
First order of business is to convert K2O to K+:
=39.09831/(39.09831+(30.9737622*2)
=0.386936386
So for every mg K2O there's 0.386936386 mg K+
It's 5% so...
=(1000/100*5)*0.386936386
=19.34681931
Total KNO3: 19.34681931g/L
So how much urea do we need to add? First lets find out how much N is in the bottle by converting NO3 to N.
First the conversion factor:
=14.00672/62.00501
=0.225896585
So for every 1g of NO3 there's 0.225896585 of N.
Next up, lets figure out how much NO3 is in the bottle and convert:
=(1000/100*1.25)*0.225896585
=2.823707313
So we need to get 2.823707313g more of N into this thing, and we need to do it through urea. Urea is (NH2)2CO. In terms of molar mass, that's 60.06g/mol. N is 14.00672g/mol.
=2.823707313*(60.06/14.00672)
=12.10789258
So that's 12.10789258g of urea.
Contents of 1L of pfertz N:
KNO3: 19.34681931g
(NH2)2CO.: 12.10789258g
For mixing this, as with any of the rest, you'll have to tinker with the order. I'm not sure what sort of issues with precipitates you might run into since I don't play with urea outside of the mens room.
The other two are way easier. The P bottle is nothing but DI H2O and KH2PO4. It lists as 0.25% K2O.
So first lets figure out how much K2O that is, and convert it to the equivalent K+:
=(1000/100*.25)*0.386936386
=0.967340965
That's 0.967340965g of K+
Now how much KH2PO4 does that require?
=0.967340965*(136.0856722/39.09831)
=3.366929299
Pfertz P contains 3.366929299g
Contents of 1L of Pferts P:
KH2PO4: 3.366929299g
And now for the K+, which is more of the same method. In this case it's all K2SO4 and listed as 5.1% K2O.
Convert % of K2O to quantity of K:
=(1000/100*5.1)*0.386936386
=19.73375569
So 19.73375569g of K, now how much K2SO4 does that mean?
=19.73375569*(174.25984/78.19662)
=43.9763395
Contents of 1L of Pferts K:
K2SO4: 43.9763395g
And there you have it. An approximation of pfertz NPK. When I have a bit more energy I may correct for density, and take a run at the micros. If anyone sees any errors, let me know. The rechecked, refined version is something I'll probably post up over on barrreport.com or something.
Enjoy
Philosophos
All of this will be working in 1L batches, you can half to get 500ml later. I'm not about to correct for density at the moment; it'd take me a while longer to calculate that and I'm a bit tired right now. You may want to add 25% to any of these numbers. You could probably even weigh some pfertz to get a rough estimate if you wanted. You'll also want to follow along with these equations by looking up the molar mass of the compounds we're working with.
Nitrogen bottle:
5% K2O
1.75% NO3
Ingredients: Urea and KNO3
Well there's no potassium in urea, so we can find out the quantity of it by figuring out however much KNO3 doesn't take up.
First order of business is to convert K2O to K+:
=39.09831/(39.09831+(30.9737622*2)
=0.386936386
So for every mg K2O there's 0.386936386 mg K+
It's 5% so...
=(1000/100*5)*0.386936386
=19.34681931
Total KNO3: 19.34681931g/L
So how much urea do we need to add? First lets find out how much N is in the bottle by converting NO3 to N.
First the conversion factor:
=14.00672/62.00501
=0.225896585
So for every 1g of NO3 there's 0.225896585 of N.
Next up, lets figure out how much NO3 is in the bottle and convert:
=(1000/100*1.25)*0.225896585
=2.823707313
So we need to get 2.823707313g more of N into this thing, and we need to do it through urea. Urea is (NH2)2CO. In terms of molar mass, that's 60.06g/mol. N is 14.00672g/mol.
=2.823707313*(60.06/14.00672)
=12.10789258
So that's 12.10789258g of urea.
Contents of 1L of pfertz N:
KNO3: 19.34681931g
(NH2)2CO.: 12.10789258g
For mixing this, as with any of the rest, you'll have to tinker with the order. I'm not sure what sort of issues with precipitates you might run into since I don't play with urea outside of the mens room.
The other two are way easier. The P bottle is nothing but DI H2O and KH2PO4. It lists as 0.25% K2O.
So first lets figure out how much K2O that is, and convert it to the equivalent K+:
=(1000/100*.25)*0.386936386
=0.967340965
That's 0.967340965g of K+
Now how much KH2PO4 does that require?
=0.967340965*(136.0856722/39.09831)
=3.366929299
Pfertz P contains 3.366929299g
Contents of 1L of Pferts P:
KH2PO4: 3.366929299g
And now for the K+, which is more of the same method. In this case it's all K2SO4 and listed as 5.1% K2O.
Convert % of K2O to quantity of K:
=(1000/100*5.1)*0.386936386
=19.73375569
So 19.73375569g of K, now how much K2SO4 does that mean?
=19.73375569*(174.25984/78.19662)
=43.9763395
Contents of 1L of Pferts K:
K2SO4: 43.9763395g
And there you have it. An approximation of pfertz NPK. When I have a bit more energy I may correct for density, and take a run at the micros. If anyone sees any errors, let me know. The rechecked, refined version is something I'll probably post up over on barrreport.com or something.
Enjoy
Philosophos


Wannabe Guru
Quote:
Originally Posted by Philosophos
View Post
Hmm looks relatively easy to deconstruct in terms of its NPK.
All of this will be working in 1L batches, you can half to get 500ml later. I'm not about to correct for density at the moment; it'd take me a while longer to calculate that and I'm a bit tired right now. You may want to add 25% to any of these numbers. You could probably even weigh some pfertz to get a rough estimate if you wanted. You'll also want to follow along with these equations by looking up the molar mass of the compounds we're working with.
Nitrogen bottle:
5% K2O
1.75% NO3
Ingredients: Urea and KNO3
Well there's no potassium in urea, so we can find out the quantity of it by figuring out however much KNO3 doesn't take up.
First order of business is to convert K2O to K+:
=39.09831/(39.09831+(30.9737622*2)
=0.386936386
So for every mg K2O there's 0.386936386 mg K+
It's 5% so...
=(1000/100*5)*0.386936386
=19.34681931
Total KNO3: 19.34681931g/L
So how much urea do we need to add? First lets find out how much N is in the bottle by converting NO3 to N.
First the conversion factor:
=14.00672/62.00501
=0.225896585
So for every 1g of NO3 there's 0.225896585 of N.
Next up, lets figure out how much NO3 is in the bottle and convert:
=(1000/100*1.25)*0.225896585
=2.823707313
So we need to get 2.823707313g more of N into this thing, and we need to do it through urea. Urea is (NH2)2CO. In terms of molar mass, that's 60.06g/mol. N is 14.00672g/mol.
=2.823707313*(60.06/14.00672)
=12.10789258
So that's 12.10789258g of urea.
Contents of 1L of pfertz N:
KNO3: 19.34681931g
(NH2)2CO.: 12.10789258g
For mixing this, as with any of the rest, you'll have to tinker with the order. I'm not sure what sort of issues with precipitates you might run into since I don't play with urea outside of the mens room.
The other two are way easier. The P bottle is nothing but DI H2O and KH2PO4. It lists as 0.25% K2O.
So first lets figure out how much K2O that is, and convert it to the equivalent K+:
=(1000/100*.25)*0.386936386
=0.967340965
That's 0.967340965g of K+
Now how much KH2PO4 does that require?
=0.967340965*(136.0856722/39.09831)
=3.366929299
Pfertz P contains 3.366929299g
Contents of 1L of Pferts P:
KH2PO4: 3.366929299g
And now for the K+, which is more of the same method. In this case it's all K2SO4 and listed as 5.1% K2O.
Convert % of K2O to quantity of K:
=(1000/100*5.1)*0.386936386
=19.73375569
So 19.73375569g of K, now how much K2SO4 does that mean?
=19.73375569*(174.25984/78.19662)
=43.9763395
Contents of 1L of Pferts K:
K2SO4: 43.9763395g
And there you have it. An approximation of pfertz NPK. When I have a bit more energy I may correct for density, and take a run at the micros. If anyone sees any errors, let me know. The rechecked, refined version is something I'll probably post up over on barrreport.com or something.
Enjoy
Philosophos
All of this will be working in 1L batches, you can half to get 500ml later. I'm not about to correct for density at the moment; it'd take me a while longer to calculate that and I'm a bit tired right now. You may want to add 25% to any of these numbers. You could probably even weigh some pfertz to get a rough estimate if you wanted. You'll also want to follow along with these equations by looking up the molar mass of the compounds we're working with.
Nitrogen bottle:
5% K2O
1.75% NO3
Ingredients: Urea and KNO3
Well there's no potassium in urea, so we can find out the quantity of it by figuring out however much KNO3 doesn't take up.
First order of business is to convert K2O to K+:
=39.09831/(39.09831+(30.9737622*2)
=0.386936386
So for every mg K2O there's 0.386936386 mg K+
It's 5% so...
=(1000/100*5)*0.386936386
=19.34681931
Total KNO3: 19.34681931g/L
So how much urea do we need to add? First lets find out how much N is in the bottle by converting NO3 to N.
First the conversion factor:
=14.00672/62.00501
=0.225896585
So for every 1g of NO3 there's 0.225896585 of N.
Next up, lets figure out how much NO3 is in the bottle and convert:
=(1000/100*1.25)*0.225896585
=2.823707313
So we need to get 2.823707313g more of N into this thing, and we need to do it through urea. Urea is (NH2)2CO. In terms of molar mass, that's 60.06g/mol. N is 14.00672g/mol.
=2.823707313*(60.06/14.00672)
=12.10789258
So that's 12.10789258g of urea.
Contents of 1L of pfertz N:
KNO3: 19.34681931g
(NH2)2CO.: 12.10789258g
For mixing this, as with any of the rest, you'll have to tinker with the order. I'm not sure what sort of issues with precipitates you might run into since I don't play with urea outside of the mens room.
The other two are way easier. The P bottle is nothing but DI H2O and KH2PO4. It lists as 0.25% K2O.
So first lets figure out how much K2O that is, and convert it to the equivalent K+:
=(1000/100*.25)*0.386936386
=0.967340965
That's 0.967340965g of K+
Now how much KH2PO4 does that require?
=0.967340965*(136.0856722/39.09831)
=3.366929299
Pfertz P contains 3.366929299g
Contents of 1L of Pferts P:
KH2PO4: 3.366929299g
And now for the K+, which is more of the same method. In this case it's all K2SO4 and listed as 5.1% K2O.
Convert % of K2O to quantity of K:
=(1000/100*5.1)*0.386936386
=19.73375569
So 19.73375569g of K, now how much K2SO4 does that mean?
=19.73375569*(174.25984/78.19662)
=43.9763395
Contents of 1L of Pferts K:
K2SO4: 43.9763395g
And there you have it. An approximation of pfertz NPK. When I have a bit more energy I may correct for density, and take a run at the micros. If anyone sees any errors, let me know. The rechecked, refined version is something I'll probably post up over on barrreport.com or something.
Enjoy
Philosophos
I am dizzy and need to go lay down.....
Algae Grower
Have you thought about dosing the PPS PRO method, 1 ml doses 10 gallons. If you reduce the quantities by half each 1 ml would dose 5 gallons.
Planted Member
I second that! Quite a science lesson in 1 post.
Planted Member
Lots of science, but no density compensation yet so the numbers are wrong. Density is going to make a huge differenced; don't go mixing anything yet based on the numbers I posted. I'm working on a more complete examination of pfertz in terms of cost compared to DIY and seachem's line of products (very similar packaging method) and I'll post a link to it when I'm done.
Philosophos
Philosophos
Planted Tank Obsessed
Yeah please! Once you figure it out people like me can just get the amounts, mix them and dose using the pfertz bottles.
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"No se vive celebrando victorias, sino superando derrotas."
Planted Member
Algae Grower
Quote:
Nitrogen bottle:
5% K2O
1.75% NO3
Ingredients: Urea and KNO3
Well there's no potassium in urea, so we can find out the quantity of it by figuring out however much KNO3 doesn't take up.
First order of business is to convert K2O to K+:
=39.09831/(39.09831+(30.9737622*2)
=0.386936386
So for every mg K2O there's 0.386936386 mg K+
It's 5% so...
=(1000/100*5)*0.386936386
=19.34681931
Total KNO3: 19.34681931g/L
5% K2O
1.75% NO3
Ingredients: Urea and KNO3
Well there's no potassium in urea, so we can find out the quantity of it by figuring out however much KNO3 doesn't take up.
First order of business is to convert K2O to K+:
=39.09831/(39.09831+(30.9737622*2)
=0.386936386
So for every mg K2O there's 0.386936386 mg K+
It's 5% so...
=(1000/100*5)*0.386936386
=19.34681931
Total KNO3: 19.34681931g/L
If one dissolves KNO3: 19.34681931g/L it will be only 0.722% of K.
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