Hello all, I've tried looking through old threads and I've come up short.
Just looking how many grams of baking soda I need to add to 1 gallon of distilled water to reach 4 dkh for my drop checker solution.
I have an accurate scale to do this.
Edit: Beh I'll just do the math. Let me know if I am wrong:
NaHCO3 = 84 g/mol
1 gal = 3.76 L
1 dkh = 17.8 ppm as CaCO3
4 dkh = 71.2 ppm
CO3 is (60 g/mol) / (84 g/mol) which is 71.4% of NaHCO3
We need mg/L which is ppm
To get 71.2 ppm of NaHCO3 in 3.76 liters (1 gallon) we need 71.2 mg/L * 3.76 L =~ 264 mg NaHCO3
However, CO3 is just 71.4% of the whole, so need to multiply result by 1.286
264mg * 1.286 =~ 340mg of NaHCO3 to reach a total of 71.2 ppm CO3
I'm a physicist by trade, but I think this is correct based on my gen chem classes five years ago