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Old 10-16-2005, 09:31 AM Thread Starter
Wö£fëñxXx
Planted Tank Guru

Join Date: Dec 2003
Location: USA
Posts: 3,037
Ogsy I came across this, I hope it will give adequate answer's for you.

Nitrate (NO3) from KNO3 (Greenlight Stump Remover)

Greenlight brand stump remover is pure potassium nitrate (KNO3).

MWs: Potassium Nitrate (KNO3) = 101.1, NO3 = 62, therefore NO3 is 61% of KNO3

From consensus on the Aquatic Pants Mailing List it is recommended to use 10 ppm KNO3 twice per week.

10 ppm NO3 = 10 mg/l NO3. Since KNO3 is 61% NO3 you need 10/.61 = 16.4 mg/l of KNO3

In 10 gallons there are 3.77 x 10 = 37.7 liters

For 10 gallons you need 37.7x16.4 = 618 mg of KNO3

To get 10 ppm NO3 from KNO3 in each 10 gallons of water add .62 grams of KNO3.

So for 100 gallons add 6.2 grams KNO3

For 75 gallon tank

For 10 ppm in 66.2 gallons (75 gal tank) use .62x(66.2/10)= 4.1 grams of KNO3 (twice per week)

For 125 gallon tank

(105.7/66.2) x 4.1 g = 6.5 g

Use 6.5 grams of KNO3 twice per week for the 125 gallon tank.

Use 2 x (1/2) teaspoon (6.2 grams = 9.5 ppm) twice per week.

Phosphate from Fleet Enema

For Generic Fleet Enema (assume anhydrous)

MWs: Monobasic Sodium Phosphate (NaH2PO4) = 120, PO4 = 95, therefore PO4 is 79% of NaH2PO4

Dibasic Sodium Phosphate (Na2HPO4) = 142, PO4 = 95, therefore PO4 is 67% of Na2HPO4

Monobasic Sodium Phosphate (NaH2PO4) = 19 g, .79 x 19 = 15.01 g PO4

Dibasic Sodium Phosphate (Na2HPO4) = 7 g, .67 x 7 = 4.69 g PO4

Total PO4 is 19.7 g in 133 ml of water. Or 148 mg/ml

For Generic Fleet Enema (assume hydrated compounds)

MWs: Monobasic Sodium Phosphate (NaH2PO4·H20) = 138, PO4 = 95, therefore PO4 is 69% of NaH2PO4·H20.

Dibasic Sodium Phosphate Na2HPO4·H20 = 160, PO4 = 95, therefore PO4 is 59% of Na2HPO4·H20.

Monobasic Sodium Phosphate (NaH2PO4·H20) = 19 g, .69 x 19 = 13.11 g PO4

Dibasic Sodium Phosphate (Na2HPO4·H20) = 7 g, .59 x 7 = 4.13 g PO4

Total PO4 is 17.24 g in 133 ml of water. Or 130 mg/ml

According to John Fitch, Fleet says that the concentration of PO4 is 131.36 mg/ml

Potassium (K) from Muriate of Potash (KCl), 0-0-60

How much KCl is needed to make 5 ppm K in a 100 gallons of water?

KCL, Muriate of Potash. The bag says 0-0-60. It also says K2O=60%. MW of K=39.1, of O=16. K2O is 83.0% K. That means the bag is .6 x .83 = 49.8% K.

5 ppm = 5 mg/L

You have 100 gal x 3.77 = 377 liters

For 5 ppm K you need 5 x 377 mg K = 1885 mg K

1885 K/.498 = 3785 mg KCl

To raise K 5 ppm in 100 gallons add 3.9 grams of KCl.

Chemical Computations

Quote:
Originally Posted by Oqsy
I have a request. could someone convert the above table for use with the following macro sources? (these items are locally available for myself and many other hobbiests where the greg watson stuff would require s&h charges)

NO3: Green Light
P: Fleet
K: KCl powder / pellets

I know Sulphur is covered by the K2SO4 many use for dosing, but is it necessary to add it to the above items in conjunction with Flourish or TMG, or should "average" tapwater contain enough of sulphur to keep plants happy?

Oqsy

Craig

Last edited by Wö£fëñxXx; 01-08-2008 at 10:37 AM.
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